x 2 a 2 + y 2 b 2 = 0 {\displaystyle {\frac {x^{2}}{a^{2}}}+{\frac {y^{2}}{b^{2}}}=0}
x 2 a 2 + y 2 b 2 = − 1 {\displaystyle {\frac {x^{2}}{a^{2}}}+{\frac {y^{2}}{b^{2}}}=-1}
x 2 a 2 + y 2 b 2 = 1 {\displaystyle {\frac {x^{2}}{a^{2}}}+{\frac {y^{2}}{b^{2}}}=1}
x 2 a 2 − y 2 b 2 = 1 {\displaystyle {\frac {x^{2}}{a^{2}}}-{\frac {y^{2}}{b^{2}}}=1}
y = a x 2 {\displaystyle y=ax^{2}}
x y = 0 {\displaystyle xy=0}
y 2 = − a 2 {\displaystyle y^{2}=-a^{2}}
y 2 = 0 {\displaystyle y^{2}=0}
y 2 = a 2 {\displaystyle y^{2}=a^{2}}
y 2 = a x ( x − p ) ( x − q ) {\displaystyle y^{2}=ax(x-p)(x-q)}
y 2 = a x ( x − p ) 2 {\displaystyle y^{2}=ax(x-p)^{2}}
y 2 = a x 3 {\displaystyle y^{2}=ax^{3}}
x ( x 2 a 2 + y 2 b 2 − 1 ) {\displaystyle x\left({\frac {x^{2}}{a^{2}}}+{\frac {y^{2}}{b^{2}}}-1\right)}
( x − a ) ( x 2 a 2 + y 2 b 2 − 1 ) {\displaystyle (x-a)\left({\frac {x^{2}}{a^{2}}}+{\frac {y^{2}}{b^{2}}}-1\right)}
( a 1 x + b 1 y + 1 ) ( a 3 x + b 3 y + 1 ) ( a 3 x + b 3 y + 1 ) {\displaystyle (a_{1}x+b_{1}y+1)(a_{3}x+b_{3}y+1)(a_{3}x+b_{3}y+1)}
( a 1 x + y ) ( a 3 x + y ) ( a 3 x + y ) {\displaystyle (a_{1}x+y)(a_{3}x+y)(a_{3}x+y)}
x y 2 {\displaystyle xy^{2}}
y 3 {\displaystyle y^{3}}
